[miss adorablexd]

okay so i realized my textbook got all its pages ripped out from the chapter i need. great. isnt it?

Please explain the steps =)
also note on teh side, im not looking for straight answers, i wanna know the steps so i can use it and try to do other probelms myslef
thank you for taking your time to help me =)


1. Find an equation for the parabola with the given vertex that passes through the given point
vertex(-2,-2), through the point (1,2)

2.Graph the function.
Choose a viewing window that shows all local maximim and minimum values and all x - intercepts. Indicate the veiwing window dimensions
y = x^3+x^2+x+5
for this i dont understand how to get the windows

3. Use a graph of the function to help suggest one linear factor. confrimt he factor algebraically
f(x)=2x^3+x^2-2x-6

that is all for now =)

[cyberfruit]

Do you have a graphing calculator?

In order to find the x and y-intercepts on the calculator, you would have to do 2nd+Trace then choose 3. Minimum, 4. Maximum, or 5. Intersect.

The Window dimensions come from how much you had to zoom in order to accurately see the graph. Just press "Window" and I think you would jusr have to copy what you see.

[Vivskies]

1. Find an equation for the parabola with the given vertex that passes through the given point
vertex(-2,-2), through the point (1,2)


Use y=a(x-h)^2 + k. As you probably already know, (h,k) is the vertex.
Substitute it in.
y=a(x+2)^2-2

Plug in point (1,2) into the just derived equation to get you're "a"

2=a(1+2)^2-2
4=a(3)^2
4/9=a

And so you plug it in, but you leave (x,y) blank.
And so your formula is

y=4/9(x+2)^2-2

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On the calculator ones, I'm not to sure how to explain it...

[miss adorablexd]

thank you for all the help =)