[Vindictive]

please help me

One mole of an ideal monatomic gas initially at point A at a pressure of 1.0x10^5 Newtons per meter squared and a volume of 25x10^-3 meter cubed is taken through a three-process cycle, as shown in the pV diagram above. Each process is done slowly and reversibly. For a monatomic gas, the heat capacities for constant volume and constant pressure are respectively Cv=(3/2)R and Cp=(5/2)R where R is the universal gas constant 8.32J/moleK.

Determine:
(a) The temperature of the gas at each of the vertices, A, B, and C, of the triangular
cycle
( The net work done by the gas for one cycle.
© The net heat absorbed by the gas for one cycle.
(d) The heat given off by the gas for the third process from C to A.
(e) The efficiency of the cycle


i don't HAVE to know the answers but instead only the equation NEEDED to solve each answer :X :X

please helpppp !

[roneddski]

For (i) , u have to use the ideal gas equation: pV = nRT

where p = pressure
V = volume
n = gas amt(in moles)
R = ideal gas constant(8.314J per K per mol)
T = absolute temperature

as well as (P1.V1)/T1 = (P2.V2)/T2

where P1, V1 n T1 are pressure, volume, temp at point 1
P2, V2 n T2 are pressure, volume, temp at point 2

For (ii) , work done, W = p . dV

where p = pressure
dV = change in volume

For (iii) , to find net heat, use dU = dQ + dW

where dU = change in internal energy
dQ = change in net heat
dW = net work done on the system

Note tat the net work done was found in (ii).

For (iv) , Q = nC(dT)

where Q = the heat abosrbed or taken out
n = number of moles
c = specific heat capacity
dT = change in temperature frm C to A

For (v), effciency, n = Qout/ Qin

where Qout = the heat given out
Qin = the heat absorbed


mayb u can double check w the ans to see whther the equations i have provided are useful.
hopefully tat helps.