[akenon]

I don't usually do this, but I've been really stuck on this problem and I need to finish ._.;

I kind of get the general idea that you'll want to put the speakers at a point where you can't hear the sound anymore due to destructive interference, but that's about as much as I've got right now :T

Thanks in advance!

Your teacher gives you two speakers that are in phase and emitting the same frequency of sound, which is between 5000 and 10000 Hz. She asks you to determine this frequency more precisely. She does not have a frequency or wavelength meter in the lab, so she asks you to design an interference experiment to determine the frequency. The speed of sound is 340 m/s at the temperature of the lab room.

a) From the list below, selesct the additional equipment you will need to do your experiment by checking the line next to each.
_ speaker stand
_ meterstick
_ ruler
_ tape measure
_ stopwatch
_ sound-level meter

Draw a labeled diagram of the experimental setup that you would use. On the diagram, use symbols to identify what measurements you will need to make.

c) Briefly outline the procedure that you would use to make the needed measurements, including how you would use each piece of equipment you checked in (a).

d) Using equations, show explicitly how you would use your measurements to calculate the frequency of the sound produced by the speakers.

e) If the frequency is decreased, describe how this would affect your measurements.

[Voltage]

I think this should work:

Point the speakers directly opposite of each other. Align them so that they are out of phase(leave one static and move the other), it will be a distance between 0 cm and 3.4 cm before you hear stuff and don't hear stuff. Using your sound-level meter, ensure that the when adjusting the position, the decibal reading is as close to 0 as possible. Next, measure the distance required to hear when the two speakers are in phase such that the db reading is now double the amplitude of a single speaker. The distance measured between 0 to peak amplitude is half the wavelength. Double the distance or just measure the distance between a peak-null-peak. 340/(distance peak to peak) is the frequency.

[akenon]

Thank you so much!! :'D
You saved my life points haha