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Parametric Equations does anyone know how to do it?

#1 User is offline   魚燕往返 

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Post icon  Posted 09 May 2008 - 07:34 PM

nvm, i figured it out. Thanks to those who replied, appreicate it!
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#2 User is offline   Bamboo 

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Posted 09 May 2008 - 09:02 PM

Post the problem. I might be able to help you. If not, I know someone who can.
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#3 User is offline   魚燕往返 

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Posted 09 May 2008 - 09:22 PM

nvm, got it. Thanks for the replies!
我不会再相信爱情了。这样你满意了吧?
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#4 User is offline   Voltage 

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Posted 10 May 2008 - 09:25 AM

call horizontal axis x, vertical axis y

f(t) = (x(t),y(t)) = (22cos(w_0*t), 12sin(w_0*t))

Period is given as 5 seconds
=> (2*pi)/T = w_0 "or the natural frequency"

Some discrepancies in the image as well

is the arm moving in the counter clockwise direction? or is it that the arm traveled pi/3 after .3 revolutions?

If traveling clockwise, f(t) = (x(t),y(-t) = (22cos(w_0*t), -12sin(w_0*t))

If the problem wants that after 4.3 revolutions the arm is now at the location indicated but not necessarily moving in that direction:
f(t) = x(t+pi/2),y(-t+pi/4) = (22cos(w_0*t+pi/2),-12sin(w_0*t + pi/2))

If I'm making some incorrect assumptions, just let me know or repost the original problem


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#5 User is offline   魚燕往返 

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Posted 10 May 2008 - 11:55 AM

nvm, got it. Thanks for replying!
我不会再相信爱情了。这样你满意了吧?
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#6 User is offline   Bamboo 

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Posted 10 May 2008 - 08:09 PM

QUOTE (魚燕往返 @ May 10 2008, 12:55 PM) <{POST_SNAPBACK}>
the arrow on the right side is moving clockwise..and pi/3 angle is the starting point after 0, need to adjust it. I'm confused about (22cos(w_0*t), 12sin(w_0*t)) , what does the (w_0*t) mean? in my class inside the paraenthesis we usually just put c=2pi/period. If it's possible can you explain hwo to get the initial and terminal points also? Thank you.

I think "w_0" is "omega naught" or "omega sub zero," and the "t" is just the usual "t" in parametric equations. I only know basic parametrics, but I think it's supposed to be x(t) = 11cos(w_0*t) and y(t) =6sin(w_0*t). The coefficients of the trig functions should be half the lengths of the major and minor axes.

This site might help.
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#7 User is offline   sushiwhore 

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Posted 10 May 2008 - 08:14 PM

i'm of no help but when you said parametric i thought of the company >.>


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