nvm, i figured it out. Thanks to those who replied, appreicate it!
Page 1 of 1
Parametric Equations does anyone know how to do it?
#2
Posted 09 May 2008 - 09:02 PM
Post the problem. I might be able to help you. If not, I know someone who can.
Tact is for people who aren't witty enough to be sarcastic.
Fate is for the lazy.
Fate is for the lazy.
#4
Posted 10 May 2008 - 09:25 AM
call horizontal axis x, vertical axis y
f(t) = (x(t),y(t)) = (22cos(w_0*t), 12sin(w_0*t))
Period is given as 5 seconds
=> (2*pi)/T = w_0 "or the natural frequency"
Some discrepancies in the image as well
is the arm moving in the counter clockwise direction? or is it that the arm traveled pi/3 after .3 revolutions?
If traveling clockwise, f(t) = (x(t),y(-t) = (22cos(w_0*t), -12sin(w_0*t))
If the problem wants that after 4.3 revolutions the arm is now at the location indicated but not necessarily moving in that direction:
f(t) = x(t+pi/2),y(-t+pi/4) = (22cos(w_0*t+pi/2),-12sin(w_0*t + pi/2))
If I'm making some incorrect assumptions, just let me know or repost the original problem
f(t) = (x(t),y(t)) = (22cos(w_0*t), 12sin(w_0*t))
Period is given as 5 seconds
=> (2*pi)/T = w_0 "or the natural frequency"
Some discrepancies in the image as well
is the arm moving in the counter clockwise direction? or is it that the arm traveled pi/3 after .3 revolutions?
If traveling clockwise, f(t) = (x(t),y(-t) = (22cos(w_0*t), -12sin(w_0*t))
If the problem wants that after 4.3 revolutions the arm is now at the location indicated but not necessarily moving in that direction:
f(t) = x(t+pi/2),y(-t+pi/4) = (22cos(w_0*t+pi/2),-12sin(w_0*t + pi/2))
If I'm making some incorrect assumptions, just let me know or repost the original problem
#6
Posted 10 May 2008 - 08:09 PM
QUOTE (魚燕往返 @ May 10 2008, 12:55 PM) <{POST_SNAPBACK}>
the arrow on the right side is moving clockwise..and pi/3 angle is the starting point after 0, need to adjust it. I'm confused about (22cos(w_0*t), 12sin(w_0*t)) , what does the (w_0*t) mean? in my class inside the paraenthesis we usually just put c=2pi/period. If it's possible can you explain hwo to get the initial and terminal points also? Thank you.
I think "w_0" is "omega naught" or "omega sub zero," and the "t" is just the usual "t" in parametric equations. I only know basic parametrics, but I think it's supposed to be x(t) = 11cos(w_0*t) and y(t) =6sin(w_0*t). The coefficients of the trig functions should be half the lengths of the major and minor axes.
This site might help.
Tact is for people who aren't witty enough to be sarcastic.
Fate is for the lazy.
Fate is for the lazy.
#7
Posted 10 May 2008 - 08:14 PM
i'm of no help but when you said parametric i thought of the company >.>
SUSHIWHORE'S W.A.N.T.E.D list (store!)
Seven for All Mankind- Rock& Republic- Thrift Bin- Misc!
B&A Makeup; Indiv. Lash Tut. ;; Wavy Hair Tut.;;FACEBOOK IT
Seven for All Mankind- Rock& Republic- Thrift Bin- Misc!
B&A Makeup; Indiv. Lash Tut. ;; Wavy Hair Tut.;;FACEBOOK IT
Share this topic:
Page 1 of 1













